Daniil Medvedev (file photo) REUTERS
Daniil Medvedev was knocked out in the fourth round of Indian Wells by Bulgarian Grigor Dimitrov on Wednesday as the world number two’s near-perfect start turned nightmarish in a 4-6 6-4 6-3 loss.
Medvedev broke Dimitrov’s serve to open the game, facilitating an almost perfect first set in which he won all but four of his first serve points and notched three aces with just five unforced errors.
The Russian, who won his first major US Open title last month, was two breaks ahead in the second set and looked on his way to an easy victory.
But Dimitrov came back strong, winning five straight games to gain control of the momentum as Medvedev unraveled, converting at the breaking point to close the second set, before winning three more straight matches to open the third.
Down 15-40, 4-1, Medvedev’s frustrations boiled over as he missed a first serve and angrily threw his racquet to the ground. He then committed a double fault, Dimitrov giving the break.
Medvedev fired back and then maintained the serve, but it was too late as the world number 28 made a stunning comeback in the next game, before raising his arms in triumph.
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